Answer
0.0186 M/min
Work Step by Step
Average rate=$\frac{1}{2}\times\frac{\Delta [NH_{3}]}{\Delta t}$
$=\frac{1}{2}\times\frac{0.815M-0.257M}{15.0 min}= 0.0186 M/min$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 11 - Chemical Kinetics: Rates of Reactions - Questions for Review and Thought - Topical Questions - Page 523a: 18c
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