Answer
The concentration of $NaNO_3$ is equal to 0.214 M.
Work Step by Step
1. Calculate the molar mass $(NaNO_3)$:
22.99* 1 + 14.01* 1 + 16* 3 = 85g/mol
2. Calculate the number of moles $(NaNO_3)$
$n(moles) = \frac{mass(g)}{mm(g/mol)}$
$n(moles) = \frac{ 45.4}{ 85}$
$n(moles) = 0.5341$
3. Find the concentration in mol/L $(NaNO_3)$:
$C(mol/L) = \frac{n(moles)}{volume(L)}$
$ C(mol/L) = \frac{ 0.5341}{ 2.5} $
$C(mol/L) = 0.214$
