Answer
44.6 g of $KBr$
Work Step by Step
- Convert the volume to liters:
$250.0 mL \times \frac{1L}{10^3L} = 0.2500 L$
1. Find the number of moles:
$Concentration(M) = \frac{n(mol)}{V(L)}$
$1.5 = \frac{n(mol)}{0.2500}$
$1.5 * 0.25000 = n(mol)$
$0.375 moles = n(mol)$
2. Determine the molar mass of this compound (KBr):
39.1* 1 + 79.9* 1 = 119.0g/mol
3. Calculate the mass
$mm(g/mol) = \frac{mass(g)}{n(mol)}$
$mm(g/mol) * n(mol) = mass(g)$
$ 119 * 0.375 = mass(g)$
$44.6 = mass(g)$
