Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 16 - Exercises - Page 772: 55

Answer

The pHs are, respectively: 1.36, 1.35, 1.34. As we can see, when we change the second significant digit in the concentration, the pH value only changes the number in the second decimal place. This will happen due to the properties of the log 10 function. Therefore, it is important to use the significant figures of pH in this way, so we do not round the value too much.

Work Step by Step

We find: $$pH = -log[H_3O^+] = -log( 0.044 ) = 1.36 $$ $$pH = -log[H_3O^+] = -log( 0.045 ) = 1.35 $$ $$pH = -log[H_3O^+] = -log( 0.046 ) = 1.34 $$
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