Answer
a. $$pH = 7.77 $$
$$pOH = 6.23$$
b. $$pH = 7.00 $$
$$pOH = 7.00 $$
c. $$pH = 5.66 $$
$$pOH = 8.34 $$
Work Step by Step
We find:
a. $$pH = -log[H_3O^+] = -log( 1.7 \times 10^{-8} ) = 7.77 $$
$$pOH = 14 - 7.77 = 6.23$$
b. $$pH = -log[H_3O^+] = -log( 1.0 \times 10^{-7} ) = 7.00 $$
$$pOH = 14 - 7.00 = 7.00 $$
c. $$pH = -log[H_3O^+] = -log( 2.2 \times 10^{-6} ) = 5.66 $$
$$pOH = 14 - 5.66 = 8.34 $$
