Answer
The equilibrium constant at this temperature is equal to $136$
Work Step by Step
1. The exponent of each concentration is equal to its balance coefficient.
$$K_C = \frac{[Products]}{[Reactants]} = \frac{[ CH_3OH ]}{[ CO ][ H_2 ] ^{ 2 }}$$
2. Substitute the values and calculate the constant value:
$$K_C = \frac{( 0.185 )}{( 0.105 )( 0.114 )^{ 2 }} = 136$$
