Answer
$V2 = 1.146m^{3}$
Work Step by Step
data:
initial volume= $V1= 1.50l= 0.0015m^{3}$
$pressure= P= 1.22 × 10^{5} Pa$
heat absorbed = $q = 1.25KJ=1.25× 10^{3}$
change in internal energy = $ΔU = 1.11KJ=1.11× 10^{3}$
to find:
final volume = V2 = ?
formula used:
Δ V = V2-V1
ΔU = q + PΔ V
solution:
PΔ V = ΔU - q
$PΔ V = 1.11× 10^{3} - 0.0015m^{3}$
$PΔ V = -1.4×10^{5}$
$Δ V = -1.4×10^{5}/1.22 × 10^{5} Pa$
$Δ V = 1.147m^{3}$
as
Δ V = V2-V1
V2 = ΔV - V1
$V2 = 1.147m^{3} - 0.0015m^{3}$
$V2 = 1.146m^{3}$
