Answer
change in volume is 10 litre.
Work Step by Step
data:
work done by the system =$W =1.34KJ=1.34× 10^3J $
pressure= $P= 1.33 × 10^5 Pa$
to find:
change in volume = Δ V =? in litre
formula used:
W = PΔ V
by rearranging we get
Δ V = W / P
solution:
Δ V = W / P
$Δ V = (1.34 × 10^3J) / (1.33 × 10^5 Pa)
as
1pa = 1 Kg/m.s^2$
so by converting into required units
$Δ V = (1.34 × 10^3 Kgm^2/s^2) / (1.33 × 10^5Kg/m.s^2)$
$Δ V = 1.00 × 10^-2 m^3$
as
$1m^3 = 1000l$
Δ V = 10 l
so change in volume is 10 litre.
