Answer
$21.9\ mg$
Work Step by Step
Number of moles of NaOH:
$0.0102\ M\times 33.51\ mL=0.341\ mmol$
From stoichiometry:
$0.114\ mmol$ citric acid.
Mass of acid:
$0.114\ mmol\times 192.13\ mg/mmol=21.9\ mg$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179i: 106
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