Answer
$1.54\ g$
Work Step by Step
Number of moles of sodium bicarbonate:
$15.0\ g\div 84.01\ g/mol=0.179\ mol$
Number of moles of acetic acid:
$0.15\ M\times 0.125\ L=0.0188\ mol$, limiting reactant.
Mass produced:
$0.0188\ mol\times 82.03\ g/mol=1.54\ g$