Answer
C
Work Step by Step
Number of moles of $OH^-$
$1.71\ g\div 171.34\ g\ Ba(OH)_2/\ mol\ Ba(OH)_2\times2\ mol\ OH^-/mol\ Ba(OH)_2=0.0200\ mol$
Concentration:
$C=0.0200\div(250/1000)=0.0798\ mol/L$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - 4-5 Measuring Concentrations of Compounds in Solution - Review & Check for Section 4-5 - Page 161: 1
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