Answer
C
Work Step by Step
$CO_2$: $1.316\ g\div44.01\ g/mol=0.0299\ mol$
C: $0.0299\ mol\times12.01\ g/mol=0.359\ g$
$H_2O$: $0.269\ g\div18.01\ g/mol=0.0149\ mol$
H: $2\times0.0149\ mol\times1.008\ g/mol=0.0300\ g$
O: $(0.509-0.359-0.0300)\ g\div 16.00\ g/mol=0.00750\ mol$
Dividing by the smallest value:
C: $0.0299/0.00750=4.0$
H: $2\times0.0149/0.00750=4.0$
Empirical formula:
$C_4H_4O$