Answer
See the answer below.
Work Step by Step
a) Reaction:
$HPO_4^{2-}+OH^-\leftrightarrow PO_4^{3-}+H_2O$
b) $OH^-$ is a stronger base than $HPO_4^{2-}$, so the equilibrium lies to the right.
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629c: 39
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