Answer
$P_2=0.075\ atm$
Work Step by Step
a) From the given data:
$r=0.17/h\times0.010\ M=0.0017\ M/h$
b) For first-order reactions:
$t_{1/2}=0.693/k=4.08\ h$
c) Knowing that $P\propto C$, initially there is 0.010 M and 0.05 atm, after one half life, there is 0.005 M of SO2Cl2, 0.005 M of SO2 and 0.005 M of Cl2 so:
$P_2/0.05\ atm=0.015/0.010\rightarrow P_2=0.075\ atm$
