Answer
$53.0\ kJ/mol$
Work Step by Step
From the linear regression of ln k vs 1/T
$\ln k=-6373.3\ K/T+18.19$
$E_a=6373.3\ K\times8.314\ J/mol.K=53.0\ kJ/mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553g: 69
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