Answer
$-\Delta[O_3]=0.001\ mol/L.s$
Work Step by Step
From stoichiometry:
$-\frac{\Delta[O_3]}{2}=\frac{\Delta[O_2]}{3}$
$-\Delta[O_3]=2/3\times1.5\times10^{-3}\ mol/L.s=0.001\ mol/L.s$
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