Answer
See the answer below.
Work Step by Step
From stoichiometry:
a) $-\frac{\Delta[NO]}{2}=-\frac{\Delta[Br_2]}{1}=\frac{\Delta[NOBr]}{2}$
b) $-\frac{\Delta[N_2]}{1}=-\frac{\Delta[H_2]}{3}=\frac{\Delta[NH_3]}{2}$
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