Answer
$7.72×10^{17}\ molecules/cm^3$
Work Step by Step
$PV=nRT$
$n/V=P/RT$
$n/V=(23.8/760×1\ atm)/(0.082\times 298)$
$n/V=1.28×10^{-3}\ mol/L$
Using this value, we obtain:
$1.28×10^{-3}\ mol/L×1\ L/1000\ cm^3×6.022×10^{23}\ molecule/mol=$
$7.72×10^{17}\ molecules/cm^3$