Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403g: 83

Answer

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Work Step by Step

From Graham's law: $0.033\ mol/60\ s\div 0.033\ mol/104\ s=\sqrt{x/44.0}$ $x=132.2\ g/mol$
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