Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic - Page 82: 90c

$111\ kg\ Mn $

1. Use Avogadro's number to convert from atoms to moles of manganese. Then use the molar mass of manganese to convert from moles to grams of manganese. Finally, convert grams into kilograms. 2. $1.22\times10^{27}\ atoms\ Mn\times\frac{1\ mol\ Mn}{6.022\times 10^{23}\ atoms\ Mn}\times\frac{54.94\ g \ Mn}{1\ mol\ Mn}\times\frac{1\ kg\ Mn}{1000\ g\ Mn}= 111\ kg\ Mn $