Answer
$ 62\ g\ Pb $
Work Step by Step
1. Use Avogadro's number and the molar mass of lead as conversion factors in order to determine the number of grams of lead.
2. $1.8\times10^{23}\ atoms\ Pb\times\frac{1\ mol\ Pb}{6.022\times 10^{23}\ atoms\ Pb}\times\frac{207.2\ g \ Pb}{1\ mol\ Pb} = 62\ g\ Pb $
