Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Cumulative Problems - Page 83: 117

Answer

$75\%$ $Au,$ $25\%$ $Pd.$

Work Step by Step

1. One mole of atoms contains $ 6.022\times10^{23}$ atoms. Therefore $\frac{2.49 \times 10^{23} }{6.022\times10^{23}} = 0.4135$ mole of atoms. 2. Now we compute number of moles of individual element using the following 1 mole of gold = 197.0 g 1 mole of palladium = 106.4 g $mole Au + mole Pd = 0.4135 $ $mole Au\times 197 + mole Pd\times106.4 = 67.2$ Two equations in two unknowns, simplify them to get mole Au =$0.2561$ mole Pd = $0.1574$ 3. We need amount of Au, So grams Au = $0.2561 \times197 = 50.45 g $ 4. Percentage conversion $50.45 / 67.2 = 0.75 (75\% Au)$
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