Answer
$2.3\times10^{17}\ automobiles$
Work Step by Step
1. Compute the mass of 1.0 mol of blueberries using conversion factors.
$1\ mol \ blueberry\times\frac{6.022\times10^{23}\ blueberry}{1\ mol \ blueberry}\times\frac{0.75\ g}{1\ blueberry}= 4.5165\times10^{23}\ g$
2. Divide the mass of these blueberries by the mass of an automobile in order to determine how many automobiles are needed to equal the mass of the blueberries.
$n= \frac{4.5165\times10^{23}\ g}{2\times10^{3}\times10^3\ g}= 2.3\times10^{17}\ automobiles$
