Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 19 - Sections 19.1-19.12 - Exercises - Cumulative Problems - Page 947: 80d

Answer

$^{85}_{41}Nb → ^{85}_{40}Zr + ^{0}_{1}e$

Work Step by Step

Nb-85 undergoes positron emission to form Zr-85.
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