Answer
$^{216}_{88}Ra → ^{216}_{87}Fr + ^{0}_{1}e$
Work Step by Step
Ra-216 undergoes positron emission to form Fr-216.
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 19 - Sections 19.1-19.12 - Exercises - Cumulative Problems - Page 947: 79b
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