Chapter 18 - Sections 18.1-18.9 - Exercises - Problems by Topic - Page 905: 53d

$E^{o}_{Cat} = -1.185$ $E^{o}_{An} = +0.126$ $E^{o}_{cell} = E^{o}_{Cat} - E^{o}_{An} = -1.1856 - 0.126$ = -1.059 Since the value is negative, the redox reaction does not occurs spontaneously in the forward direction.

Here Mn is acting as cathode and Pb is acting as anode.