Chapter 18 - Sections 18.1-18.9 - Exercises - Problems by Topic - Page 905: 53a

$E^{o}_{Cat} = -0.76$ $E^{o}_{An} = -0.23$ $E^{o}_{cell} = E^{o}_{Cat} - E^{o}_{An} = -0.76 - (-0.23)$ = -0.53 Since the value is negative, the redox reaction does not occurs spontaneously in the forward direction.

Here Ni is acting as anode and Zn is acting as cathode.