Answer
a) $N_{2}O_{4}$ - Dinitrogen tetroxide
b) $ICl_{3}$ - Iodine trichloride
c) $SO_{2}$ - Sulfur dioxide
d) $P_{2}S_{5}$ - Phosphorus pentasulfide
Work Step by Step
a) The picture has two nitrogen atoms - thus dinitrogen [ Di - two ] ,
And with them, are 4 oxygen atoms - thus tetroxide [ tetra - four ].
So, the compound is named dintrogen tetroxide.
b) The picture contains one iodine atom, and three chlorine atoms, and thus trichloride [ tri - three ]. So, the compound is named iodine trichloride
c) There are two oxygen atoms and one sulfur atom, and thus the name Sulfur dioxide [ di - two ]
d) Since there are five sulfur atoms, and hence the name phosphorus pentasulfide [penta - five]
