Answer
a) Chromium (III) Hydroxide - $Cr(OH)_{3}$
b) Magnesium cyanide - $Mg(CN)_{2}$
c) Lead (IV) Carbonate - $Pb(CO_{3})_{2}$
d) Ammonium acetate - $C_{2}H_{7}NO_{2}$
Work Step by Step
a) Chromium (III) ($Cr^{3+}$) + Hydroxide ($OH^{-}$) $\longrightarrow$ $Cr(OH)_{3}$
b) Magnesium ($Mg^{2+}$) + Cyanide ($CN^{-}$) $\longrightarrow$ $Mg(CN)_{2}$
c) Lead(IV) ($Pb^{4+}$) + Carbonate ($CO_{3}^{2-}$) $\longrightarrow$ $Pb(CO_{3})_{2}$
d) Ammonium ($NH_{4}^{+}$) + Acetate ($CH_{3}COO^{-}$) $\longrightarrow$ $C_{2}H_{7}NO_{2}$
