Answer
Yes, the resulting solution has the correct molarity.
Work Step by Step
$500$ mL = $500 \times 10^{-3}$ L = 0.500 L
1. Calculate the molar mass $(KCl)$:
39.1* 1 + 35.45* 1 = 74.55g/mol
2. Calculate the number of moles $(KCl)$
$n(moles) = \frac{mass(g)}{mm(g/mol)}$
$n(moles) = \frac{ 37.3}{ 74.55}$
$n(moles) = 0.500$
3. Find the concentration in mol/L $(KCl)$:
$C(mol/L) = \frac{n(moles)}{volume(L)}$
$ C(mol/L) = \frac{ 0.500}{ 0.500} $
$C(mol/L) = 1.00$
