Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 3 - Mass Relationships in Chemical Reactions - Section Problems - Page 106: 54

Answer

There are $ 6.44\times 10^{- 4}$ moles of caffeine in a cup, which is equal to $3.88 \times 10^{20}$ molecules.

Work Step by Step

1. Calculate the molar mass $(C_8H_{10}N_4O_2)$: 12.01* 8 + 1.008* 10 + 14.01* 4 + 16* 2 = 194.2g/mol 2. Calculate the number of moles $(C_8H_{10}N_4O_2)$ ** 125 mg = $125 \times 10^{-3} g = 0.125 g$ $n(moles) = \frac{mass(g)}{mm(g/mol)}$ $n(moles) = \frac{ 0.125}{ 194.2}$ $n(moles) = 6.44\times 10^{- 4}$ 3. Find the number of molecules: $6.44\times 10^{- 4} mol \times \frac{6.022 \times 10^{23} molecules}{1 mol} = 3.88 \times 10^{20}$
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