Answer
There are $ 5 \times 10^{18}\ atoms$ of carbon in the period.
Work Step by Step
1. Determine the molar mass of $carbon$:
Molar mass = Molecular weight value = 12.01 $g/mol$ $(C)$
2. Calculate the number of moles and the number of atoms:
$0.0001$ $g \times \frac{1 mol (C)}{12.01g (C)} \times \frac{6.022 \times 10^{23} atoms(C)}{1 mol (C)}= 5 \times 10^{18} atoms (C)$
