Answer
The atomic weight of $Ag$ is equal to 107.9 $u$.
Work Step by Step
Atomic weight:
$(Mass^{107}Ag)(Abundance^{107}Ag)$ + $(Mass^{109}Ag)(Abundance^{109}Ag)$
$(106.9051)(0.5184) + (108.9048)(0.4816) = 107.9\ u$
Chemistry (7th Edition)
by McMurry, John E.; Fay, Robert C.; Robinson, Jill Kirsten
Published by
Pearson
ISBN 10:
0321943171
ISBN 13:
978-0-32194-317-0
Chapter 2 - Atoms, Molecules, and Ions - Section Problems - Page 74: 109
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