Answer
The atomic weight of Boron is equal to 10.8 $u$.
Work Step by Step
Atomic wheight:
$(Mass^{10}B)(Abundance^{10}B)$ + $(Mass^{11}B)(Abundance^{11}B)$
$(10.0129)(0.199) + (11.00931)(0.801) = 10.8\ u$
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