Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 7 - Section 7.4 - Periodic Trends in Properties of Elements - Checkpoint - Page 299: 7.4.2

Answer

$\therefore$ Be < B < Li is the right answer

Work Step by Step

Atomic Number of Li = 3 electronic configuration = $1s^22s^1$ Atomic Number of Be = 4 electronic configuration = $1s^22s^2$ Atomic Number of B = 5 electronic configuration = $1s^22s^22p^1$ So to the order of elements in the increasing ${I.E}_2$ will be Be < B < Li
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