Answer
d) Au$\lt$Fe$\lt$Al
Work Step by Step
Heat absorbed $q=sm\Delta T$
where s is the specific heat.
Mass m and change in temperature $\Delta T$ are same for Al, Au and Fe. But, specific heats are different.
$s_{Al}=0.900\,J/g\cdot \,^{\circ}C$
$s_{Au}=0.129\,J/g\cdot \,^{\circ}C$
$s_{Fe}=0.444\,J/g\cdot \,^{\circ}C$
Heat absorbed is more by metals with high specific heat. Therefore, metals can be arranged in order of increasing amount of heat absorbed as
$Au\lt Fe\lt Al$
