Answer
The amount of $MgCl_2$ in moles is equal to $6.00 \times 10^{-3}$.
Work Step by Step
60.0 mL = $60.0 \times 10^{-3}$ L = 0.0600 L
1. Find the number of moles:
$Concentration(M) = \frac{n(mol)}{V(L)}$
$0.100 = \frac{n(mol)}{0.0600}$
$0.100* 0.0600 = n(mol)$
$6.00 \times 10^{-3} moles = n(mol)$
