Answer
(b) $196\,J/K\cdot mol$
Work Step by Step
We find:
$\Delta S_{sub}=\frac{\Delta H_{sub}}{T_{transition}}=\frac{62.4\,kJ/mol}{(45+273.15)\,K}=\frac{62.4\times1000\,J/mol}{318.15\,K}$
$=196\,J/K\cdot mol$
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 18 - Section 18.5 - Predicting Spontaneity - Checkpoint - Page 856: 18.5.4
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