Answer
The $Ba(OH)_2$ concentration is equal to $0.47M$
Work Step by Step
1000ml = 1L
20.4ml = 0.0204 L
19.3ml = 0.0193 L
1. Find the volume necessary for an equal number of moles:
** Since $Ba(OH)_2$ has 2 $OH^-$ in it, we must multiply its concentration by 2.
$C_1 * V_1 = V_2 * C_2$
$ 0.883* 0.0204= 0.0193 * (2 * C_2)$
$ 0.0180 = 0.0193 * (2 * C_2)$
$2 * C_2 = 0.933$
$C_2 = 0.467$
