Answer
a) $K_{c} = 2.6\times10^{4}$
b) $K_{p} = 3.2\times10^{2}$
Work Step by Step
a) $K_{c} = \frac{1}{3.8\times10^{-5}} = 2.6\times10^{4}$
b) T = (727+273) K = 1000 K, $\Delta n$ = 1-2 = -1 ,
$K_{p} = K_{c}(RT)^{\Delta n} =(2.6\times10^{4})\times (\frac{0.08206L.atm}{K.mol}\times1000K)^{-1}=3.2\times10^{2}$
