Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 13 - Questions and Problems - Page 598: 13.16

Answer

(a) 25.86 g of water. (b) 1720.5 g of water.

Work Step by Step

(a) $$16.2\% = \frac{5.00}{5.00 + x} \times 100\%$$ $$\frac{16.2\%}{100 \%} = \frac{5.00}{5.00 + x} $$ $$0.162= \frac{5.00}{5.00 + x} $$ $$0.162(5.00 + x)= 5.00 $$ $$0.810 + 0.162x= 5.00 $$ $$0.162x= 4.19$$ $$x=25.86$$ (b) $$1.5\% = \frac{26.2}{26.2 + x} \times 100\%$$ $$\frac{1.5\%}{100 \%} = \frac{26.2}{26.2 + x} $$ $$0.015= \frac{26.2}{26.2 + x} $$ $$0.015(26.2 + x)= 26.2 $$ $$0.393 + 0.015x= 26.2 $$ $$0.015x= 25.807$$ $$x=1720.5$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.