Answer
(e) is the correct answer.
Work Step by Step
$$PV= nRT$$
$T/K = 150 + 273.15 = 423.15 \ K$
$$P = \frac{nRT}{V} = \frac{(10.2 \ moles)(0.0826 \ L \ atm \ K^{-1} \ mol^{-1})(423.15 \ K)}{7.5 \ L} = 47 \ atm$$
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 10 - Section 10.3 - The Ideal Gas Equation - Checkpoint - Page 441: 10.3.2
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