Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 10 - Section 10.2 - The Gas Laws - Checkpoint - Page 436: 10.2.1

Answer

e) 47.4 mL

Work Step by Step

According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$ Or $V_{2}$ = $\frac{P_{1}V_{1}}{P_{2}}$ = $\frac{1.50atm\times37.3mL}{1.18atm}$ = 47.4 mL
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