Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 8 - Periodic Relationships Among the Elements - Questions & Problems - Page 363: 8.83

Answer

$N^{3-}, O^{2-}, F^{-}$ is in the decreasing order of the atomic radius.

Work Step by Step

$N^{3-}, O^{2-}, F^{-}$ is in the decreasing order of the atomic radius. (a) $Be, Mg, Ba$. Beryllium, Magnesium, and Barium belong to group 2A. Be, Mg, and Ba are the first, second, and fifth members respectively. The atomic radius increases on moving down the group. (b) $N^{3-}, O^{2-}, F^{-}$. These are isoelectronic species with 10 electrons, but the nuclear charges of $N^{3-}, O^{2-}, F^{-}$ are 7, 8, and 9 respectively. As the nuclear charge increases atomic radius decreases in the above isoelectronic species. (c) $Tl^{3+}, Tl^{2+}, Tl^{+}$. The atomic number of Thallium is 81. $Tl^{3+}, Tl^{2+}, and Tl^{+}$ are formed by the removal of 3,2, and 1 electron from the Thallium atom respectively. As the nuclear charge remains the same, the ion with the fewest electrons is attracted more effectively.
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