Answer
3.84 kg
Work Step by Step
(197.4 atm) (20.0 L) = n (0.0821) (301)
n = 159.76 mole
159.76 mol * (24.02 g/ 1 mol N2) * (1 kg/ 1000g)
kg N2 = 3.84 kg
Chemistry (12th Edition)
by Wilbraham
Published by
Prentice Hall
ISBN 10:
0132525763
ISBN 13:
978-0-13252-576-3
Chapter 14 - The Behavior of Gases - 14.3 Ideal Gases - 14.3 Lesson Check - Page 468: 33
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