Answer
(a) $[Sr^{2+}] = 0.0105M, [OH^-] = 0.0210M$
(b) $[H^+] = [ClO^{3-}] = 0.0105M$
(c) $[K^+] = 0.0210M, [S{O_4}^{2-}] = 0.0105M$
Work Step by Step
Strong electrolytes, like strong acids and bases, and salts, are capable of ionizating completely in water, therefore:
- $[AB] = [A^+] = [B^-]$
Because the reaction:
- $AB (aq) -- \gt A^+(aq) + B^-(aq)$
Occurs for all the compound molecules.
For $Sr(OH)_2$, since there is 2 $OH^-:$
- $Sr(OH)_2(aq) -- \gt Sr^{2+}(aq) + 2OH^-(aq)$
The "$OH^-$" concentration will be the double of the base concentration.
2 * 0.0105 = 0.0210M
The same thing for $K_2SO_4$
2 * 0.0105 = 0.0210
