Answer
(a) $[H^+] = [Br^-] = 0.45M$
(b) $[K^+] = [OH^-] = 0.045M$
(c) $[Ca^{2+}] = 0.0112M$, and $[Cl^-] = 0.0224M$
Work Step by Step
Strong electrolytes, like strong acids and bases, and salts, are capable of ionizating completely in water, therefore:
- $[AB] = [A^+] = [B^-]$
Because the reaction:
- $AB (aq) -- \gt A^+(aq) + B^-(aq)$
Occurs for all the compound.
For $CaCl_2$, since there is 2 $Cl^-:$
- $CaCl_2 (aq) -- \gt Ca^{2+}(aq) + 2Cl^-(aq)$
The "$Cl^-$" concentration will be the double of the salt concentration.
2 * 0.0112 = 0.0224
