Answer
Molality of the solution is $16.76m$
Work Step by Step
Mass of benzoic acid $(C_{6}H_{5}COOH)=56.5g$
Molar mass of benzoic acid $=122.12g/mol$
Number of moles of benzoic acid $= \frac{56.5g}{122.12g/mol} = 0.4627 moles$
Volume of ethanol $(C_{2}H_{5}OH) = 350mL$
Density of ethanol $=0.789g/mL$
Mass of ethanol $(C_{2}H_{5}OH) = $ Vol. of ethanol × Density
Mass of ethanol $= 350mL×0.789g/mL = 276.15g = 0.0276kg$
$Molality = \frac{Number \: of \: moles\: of \:solute}{Mass \:of \:solvent\:(in\: kg)}$
$m= \frac{0.4627}{0.0276} \; = 16.76m$
