Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Test - Page 287: 2d

Answer

$y=\dfrac{2\pi}{3}$

Work Step by Step

RECALL: $y=\text{arcsec}{(x)} \longrightarrow \sec{y}=x$ where $y$ is in the interval $[0, \frac{\pi}{2})\cup (\frac{\pi}{2}, \pi]$. Note that: $\sec{(\frac{2\pi}{3})} = -2$ Thus, the solution to the given equation is $y=\dfrac{2\pi}{3}$.
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