Answer
55 mph
Work Step by Step
1. $R= \frac{v^{2}}{g(f+\tan\theta)}$
2. Solving for v
$v= \sqrt {gR(f+\tan\theta)}$
3. $R=1150$; $\theta = 2.1^{\circ}$; $g = 32.2$ and$f= 0.4$
$v= \sqrt {gR(f+\tan\theta)}=\sqrt {1150\times 32.2 \times(0.14+\tan 2.1^{\circ})} = 80.9 ft/s$
4. Converting to mph:
$v= 80.9 ft/s = \frac{80.9}{3600}\times 5280 = 55 mph$
